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Factor strength and ability level
Admin
It has often been claimed that the strength of g is negatively related to the ability level of the group and that g may vanish entirely if the ability level was high enough. I tried testing this in the Dutch student data given by Wicherts et al.

The DF.complete.Z object has all the test data and everything else. The unit.mean variable is the unweighted mean of all 7 subtests (standardized). I divided it into three groups, low, middle, and high scoring based on the 33th and 67th centiles.

#factor strength and mean ability level
quantile(unlist(DF.complete.Z["unit.mean"]), c(1/3, 2/3)) #find quantiles

#three groups
DF.lower = DF.complete.Z[DF.complete.Z["unit.mean"] < -0.2754322,]
DF.upper = DF.complete.Z[DF.complete.Z["unit.mean"] > 0.2303728,]
DF.middle = DF.complete.Z[DF.complete.Z["unit.mean"] < 0.2303728 & DF.complete.Z["unit.mean"] > -0.2754322,]

#schmid leiman
DF.lower.omega = omega(DF.lower[1:7])
DF.upper.omega = omega(DF.upper[1:7])
DF.middle.omega = omega(DF.middle[1:7])

#normal
DF.lower.mr = fa(DF.lower[1:7])
DF.upper.mr = fa(DF.upper[1:7])
DF.middle.mr = fa(DF.middle[1:7])


The results are puzzling. Using e.g. hierarchical omega as the measure of factor strength, the results are: low: 0.12; upper: 0.43; middle: 0.49. So the factor is much weaker in the lower scoring group.

Correlation matrices look very odd:

#cortrices
round(cor(DF.lower[1:7]),2)
round(cor(DF.upper[1:7]),2)
round(cor(DF.middle[1:7]),2)
round(cor(DF.complete.Z[1:7]),2)


> round(cor(DF.lower[1:7]),2)
ravenscore lretot nsetot voctot hfitot vantot aritot
ravenscore 1.00 0.06 0.01 -0.22 0.20 -0.12 0.08
lretot 0.06 1.00 0.01 -0.13 -0.02 0.09 0.24
nsetot 0.01 0.01 1.00 -0.30 0.13 0.03 0.00
voctot -0.22 -0.13 -0.30 1.00 -0.10 0.06 0.01
hfitot 0.20 -0.02 0.13 -0.10 1.00 0.00 0.07
vantot -0.12 0.09 0.03 0.06 0.00 1.00 -0.08
aritot 0.08 0.24 0.00 0.01 0.07 -0.08 1.00
> round(cor(DF.upper[1:7]),2)
ravenscore lretot nsetot voctot hfitot vantot aritot
ravenscore 1.00 0.01 0.04 -0.14 0.13 -0.01 -0.07
lretot 0.01 1.00 0.19 0.11 0.10 0.20 0.35
nsetot 0.04 0.19 1.00 0.11 0.03 0.06 0.41
voctot -0.14 0.11 0.11 1.00 -0.13 0.20 0.18
hfitot 0.13 0.10 0.03 -0.13 1.00 0.20 0.02
vantot -0.01 0.20 0.06 0.20 0.20 1.00 0.12
aritot -0.07 0.35 0.41 0.18 0.02 0.12 1.00
> round(cor(DF.middle[1:7]),2)
ravenscore lretot nsetot voctot hfitot vantot aritot
ravenscore 1.00 -0.03 -0.29 -0.16 -0.12 0.12 -0.32
lretot -0.03 1.00 -0.10 -0.01 -0.17 0.04 -0.27
nsetot -0.29 -0.10 1.00 -0.24 -0.05 -0.09 0.31
voctot -0.16 -0.01 -0.24 1.00 -0.32 0.06 -0.15
hfitot -0.12 -0.17 -0.05 -0.32 1.00 -0.16 -0.07
vantot 0.12 0.04 -0.09 0.06 -0.16 1.00 -0.34
aritot -0.32 -0.27 0.31 -0.15 -0.07 -0.34 1.00
> round(cor(DF.complete.Z[1:7]),2)
ravenscore lretot nsetot voctot hfitot vantot aritot
ravenscore 1.00 0.34 0.27 0.09 0.37 0.34 0.25
lretot 0.34 1.00 0.35 0.24 0.32 0.46 0.45
nsetot 0.27 0.35 1.00 0.10 0.34 0.36 0.47
voctot 0.09 0.24 0.10 1.00 0.09 0.33 0.26
hfitot 0.37 0.32 0.34 0.09 1.00 0.36 0.32
vantot 0.34 0.46 0.36 0.33 0.36 1.00 0.32
aritot 0.25 0.45 0.47 0.26 0.32 0.32 1.00


So apparently that way of dividing the groups up heavily damages the structure of the data. Why?
Admin
I'll look at it later, but have you considered this article here ? It seems that the distribution of the data may be the culprit for unexpected result in studying the SLODR.

Murray, A. L., Dixon, H., & Johnson, W. (2013). Spearman's law of diminishing returns: A statistical artifact?. Intelligence, 41(5), 439-451.
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